Wow. This is the first I heard of χ. Shouldn't it be mapped to the keyboard
somewhere?

Regards,
Elias


On 9 July 2014 00:44, David Lamkins <da...@lamkins.net> wrote:

> Thanks, Jüergen. Confirmed fixed.
>
>
>
> On Sun, Jul 6, 2014 at 7:45 AM, Juergen Sauermann <
> juergen.sauerm...@t-online.de> wrote:
>
>>  Hi David,
>>
>> thanks, fixed in SVN 363.
>>
>> Please note that using a value as right function argument of an operator
>> is IMHO a rather dubious construct. I know that IBM APL2 allows it, but
>> the
>> ISO standard is rather unclear about it. On one hand ISO defines the ⍤
>> operator
>> using a value *y *as right operator argument. On the other hand they
>> define
>> the syntax of operators and other things as as *"search the form-table
>> for ..."*
>> without ever telling how the form-table is constructed, eg. for user
>> defined
>> functions.
>>
>> A syntactically cleaner approach would be to use an axis (χ in lambdas)
>> for
>> an extra value argument of the operator (not fully tested yet):
>>
>>       ∇z←l (f foo)[x] r
>> [1]  z←(r f l) (l x r)
>> [2] ∇
>>
>>
>>             1 {⍺ ⍵} foo [{3}] 2
>>  2 1  1 3 2
>>
>> /// Jürgen
>>
>>
>>
>>
>> On 07/06/2014 12:39 AM, David B. Lamkins wrote:
>>
>> The last time I worked on my component-file code was circa SVN 220. At
>> the time, I was using a defined operator that took a constant function
>> as its right function. Something akin to this, where g would always be a
>> constant function, e.g. {1}:
>>
>> ∇z←l (f foo g) r
>>  z←(r f l) (l g r)
>> ∇
>>
>> At the time, I could call this operator as:
>>
>>       1 {⍺ ⍵} foo {3} 2
>>  2 1  1 3 2
>>
>> (The above isn't exactly what I was doing... I was using the constant
>> value by itself. That used to work. This is just illustrative of what I
>> think that call ought to do, but doesn't in the current build.)
>>
>> Interestingly, I can still use a constant function on the left of the
>> operator:
>>
>>       1 {3} foo {⍺ ⍵} 2
>>  2 3 1  1 2
>>
>> When I try to put a constant function to the right of the operator, this
>> is what happens:
>>
>>       1 {⍺ ⍵} foo {3} 2
>> VALUE ERROR
>>       1 λ2 foo λ1 2
>>         ^
>>
>> Are my expectations out of line, or is this a bug?
>>
>>
>>
>>
>>
>>
>
>
> --
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>    Albert Einstein
>
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