Rob said: > So if you mix normal matter with mirror anti-matter would the result > be: > > a: Nothing because they are mutually weakly interacting? > > or > > b: a similar reaction to matter/anti-matter mixing only with a > different particle emission? > > or > > c: other?
I'm pretty sure that the answer is (a). Interactions in quantum field theory can be written as sums of Feynman diagrams, each of which is made up of lines representing particles and vertices at which the particles interact. Each type of force has characteristic vertices. For example, the electromagnetic force has a vertex with two charged particles and a photon. This can either represent a single charged particle emitting a photon or a particle and its anti-particle annihilating to form a photon. So, for example, an electron and a positron can annihilate at a vertex forming a photon. (To conserve energy and momentum, you need at least two vertices resulting in two photons in the whole diagram.) Thus, no interaction vertices means no interaction, and hence no reaction and no particle emission. Rich _______________________________________________ http://www.mccmedia.com/mailman/listinfo/brin-l
