On Wed, 2008-12-24 at 13:16 -0500, Charlie Farinella wrote:
> I need to read in a file of 200 lines and print each out to a separate
> file.
>
> I've been stumbling with this, but I don't know how to name each outfile
> individually. I was hoping to see 200 files named tx1 - tx200, but
> instead I get tx1234..................... for 123 files and then it dies.
> Help?
>
> ==
> #!/usr/bin/perl
>
> use strict;
> use warnings;
>
> my $i = 0;
> my $outfile = "tx";
>
> open( INFILE, "speed_test.csv" );
>
> while( <INFILE> ) {
> open( OUTFILE, "> $outfile" );
> print OUTFILE "$_\n";
> close OUTFILE;
> $outfile = $outfile.$i++;
This appends $i to the end of the string; This is not what you specified
above.
> }
> ==
#!/usr/bin/perl
use strict;
use warnings;
my $i = 0;
my $outfile = "tx";
open( my $infile_fh, '<', "speed_test.csv" ) or die "could not open
speed_test.csv: $!\n";
# You should always test an open
while( <$infile_fh> ) {
my $file = $outfile . ( ++ $i );
open( my $out_fh, '>', $file ) or die "could not open $file:
$!\n";
print $out_fh or die "could not print to $file: \n";
# prints $_ by default, $_ has a newline since it hasn't been
chomp'ed
close $out_fh or die "could not close $file: $!\n"
# You should always test prints and closes except for STDOUT
and STDERR
}
--
Just my 0.00000002 million dollars worth,
Shawn
Believe in the Gods but row away from the rocks.
-- ancient Hindu proverb
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