On Fri, Aug 15, 2008 at 9:03 AM, Chris Charley <[EMAIL PROTECTED]> wrote:
> On Wed, Aug 13, 2008 at 10:05 AM, John W. Krahn <[EMAIL PROTECTED]> wrote:
>>
>> Kashif Salman wrote:
>>>
>>> Greetings,
>>>>
>>>>
>>> Hello,
>>>
>>> I have a log file like so, and I am trying to get the date on the next
>>>
>>>> line
>>>> after "Start..." line. So for the log below I'd like to get the output
>>>>
>>>> 04/06/05
>>>> 05/06/05
>>>> 06/06/05
>>>>
>>>> But I also need to re-format that so the end result becomes:
>>>>
>>>> 2005-04-06
>>>> 2005-05-06
>>>> 2005-06-06
>>>>
>>>> Any hints?
>>>>
>>>>
>>> while ( <> ) {
>>> /^Start/ && <> =~ /^(\d+)\/(\d+)\/(\d+)/ && print "20$3-$1-$2";
>>> }
>>>
>>>
>>> John
>>>
>>
>
>> /^Start/ && <> =~ /^(\d+)\/(\d+)\/(\d+)/ && print "20$3-$1-$2";
>>
>>
>> I understand most of what is going on in the above line except the " && <>
>> "
>> part. Can somebody please explain that? Somehow it searches for "Start" in
>> the beginning of the line and gets the date from the next line.
>>
>>
> The <> operator is in scalar context, so it reads the next line (after
> Start) *and* performs a match on that line. In the match, it captures 3
> groups of your date digits and, if the match succeeds, prints them out in
> the form yyyy-mm-dd.
>
> $1 is the first captured digits, $2 is the second capture, etc.
>
> Hope this helps,
> Chris
>
>
How can I capture "Start" as well? putting brackets around it like so
doesn't work:
/^(Start)/ && <> =~ /^(\d+)\/(\d+)\/(\d+)/ && print "$1=> 20$4-$2-$3";
I know it seems pointless to capture start but it doesn't always say "Start"
so I want to capture it. for simplicity lets keep it "Start" and try to
capture it.
