Dr. Rudd: Thank you. That worked. I read up some docs on perlre. I know what .* does. But couldn't figure out what does .*? does. Can Someone explain what that ? does Also in the variant you suggested what does [^)] inside the paranthesis do? Thanks Ravi ----- Original Message ---- From: Dr.Ruud <[EMAIL PROTECTED]> To: beginners@perl.org Sent: Sunday, June 15, 2008 8:55:31 PM Subject: Re: Including the carriage return in extraction
Ravi Malghan schreef: > Hi: I want to extract data between the first parenthesis and the last > in the below variable. I have tried a number of combinations. I > either miss the entire string or get data only until the first > carriage return. Can someone help me to extract the data including > the carriage return between the parenthesis? $OrigString = > "REQUEST(SERVICE,1DJGHKDFJGHDFJGHKDFJH\nDFJHGDFJHGJDFHGJKDFHG\nHGJDFHGJK DFHGJKDFHGJKDFH);"; > $OrigString =~ m/REQUEST\((.*)\);/; > print "$1\n"; Read perlre, about the s-modifier. I also added non-greediness. $OrigString =~ m/REQUEST\((.*?)\);/s; Or use this variant: $OrigString =~ m/REQUEST\(([^)]*)\);/; -- Affijn, Ruud "Gewoon is een tijger." -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
