Steve Bertrand wrote:
The \w character class matches any "word" character where "word" is
defined as any alphabetic character or any numerical digit or the '_'
character. The '|' which is used for alternation outside of a
character class just matches a literal '|' character inside a
character class. The \s character class matches any whitespace character.
Ok, it makes sense now that I know that the '|' is literal in the
context that I had it.
This is more about receiving feedback and not about an answer, so as
I go find out why things work as they have been described, would you
project the statement as if you had written it yourself, just for
comparison sake?
I don't think I understand your last question.
What I mean is, if you were to use a regex as opposed to using split(),
how would you have written:
if (/.*simscan~\[\d+\]~([\w|\s]+).*?~(\d+\.\d+)s~.*?~(.*?)~(.*?)~(.*)/) {
...to do the task I originally requested help with?
Aside from removing .* at the beginning and removing '|' from the
character class the other parts should work as desired.
John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
in short order. -- Larry Wall
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
http://learn.perl.org/
