On Fri, May 2, 2008 at 5:08 PM, Joshua Hoblitt <[EMAIL PROTECTED]> wrote:
snip
>  They are probably undefinately because the record seperator is being set
>  lexically inside of the loop (and thus won't apply to the outer while).  
> Please
>  consider this code:
>
>
>     local $/ = "\n\n";
snip

An important nitpick: that is a localized version of $/, not a lexical
version.  See

http://perldoc.perl.org/functions/local.html

for more information.

-- 
Chas. Owens
wonkden.net
The most important skill a programmer can have is the ability to read.

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