Chas. Owens wrote:
On Sat, Apr 19, 2008 at 6:08 PM, Richard Lee <[EMAIL PROTECTED]> wrote:
snip
sub process_it {
my($variable, $hash_table) = shift;
}
when I change to separate shift
my $variable = shift;
my $hash_table = shift;
it worked... are they different?
snip
Yes, shift returns one item from the array it is working on, so the
first is like saying
my ($variable, $hash_table) = 5;
$variable will be 5 and $hash_table will be undefined. To get what
you want you must either say
my ($variable, $hash_table) = (shift, shift);
It would be better to do:
my ($variable, $hash_table) = splice @_, 0, 2;
Then you are guaranteed that $_[0] goes to $variable and $_[1] goes to
$hash_table.
John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
in short order. -- Larry Wall
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