thanks to your quickly answer.
now, i know :
>>'foo' is a key in symbol table,whose corresponding value is *foo.
is *foo itself a hash too? *foo{SCALAR},*foo{ARRAY}...are reference to
$foo, @foo,....
is that right?
and i want to know why *foo == *{*foo}.
thanks very much.
On Jan 23, 2008 11:43 PM, Jeff Pang <[EMAIL PROTECTED]> wrote:
>
>
> -----Original Message-----
> >From: Enjoy_Life <[EMAIL PROTECTED]>
>
> >
> >$foo = "Some value";
> >*foo{PACKAGE}; #(1)
> >*{*foo}{PACKAGE}; #(2)
> >
> >why the value of (1) and (2) are equal?
>
> This is because *foo == *{*foo}.
>
> >does that means foo is equals to *foo?
> >
>
> No.'foo' is a key in symbol table,whose corresponding value is *foo.
> see this test:
>
> $ perl -le 'our $foo;print $::{foo}'
> *main::foo
>
> here *main::foo == *foo. %:: is the symbol table entry.
>
> Regards,
> Jeff Pang
>
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