Jeff Pang schreef:
> Reference is also a scalar, when passing or returning a scalar, you
> don't need to use its reference. Passing or returning the scalar
> itself is good enough.
Yes, and that even if the sub needs to be able to change the value of
the original, because parameters are passed as aliases:
$ perl -wle '
sub doit { $_[0] = "dirty"; }
my $foo = my $bar = "clean";
print "$foo, $bar";
doit $foo, $bar;
print "$foo, $bar";
'
clean, clean
dirty, clean
--
Affijn, Ruud
"Gewoon is een tijger."
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