I am trying to format some numbers so single digit numbers are converted to
2 digit numbers and here is the code I am working with right now. For some
reason, the very last number, $b5, ends up as a 3 digit number instead of a
2 digit number even if I start it with a single digit number. If I add
chop($bcol); to the code, it cuts the last digit off but what if I do not
need to have that happen? I am not exactly new to perl but this has me
stumped.
print "Content-type: text/html\n\n";
$b1=11;
$b2=2;
$b3=5;
$b4=1;
$b5=12;
$bcol=printf("%02d %02d %02d %02d %02d", $b1, $b2, $b3, $b4, $b5);
#chop($bcol);
print qq($bcol);
Can anyone help?
Julie A. Bolduc
Owner, JPF Crochet Club
http://www.jpfun.com
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
http://learn.perl.org/