That perldoc has said, a list is a value while an array is a variable. so [EMAIL PROTECTED] get what you wanted but \(1,2,3) returns each elements' reference.
also @array = (1,2,3) will convert a list to an array automatically, and mysub(@array) will set an array as a list automatically. and you can shift/pop/unshift/push with an array not a list,if you do those with a list,you'll get errors: $ perl -Mstrict -Mwarnings -e 'pop (1,2,3)' Type of arg 1 to pop must be array (not list) at -e line 1, at end of line Execution of -e aborted due to compilation errors. $ perl -Mstrict -Mwarnings -e 'shift (1,2,3)' Type of arg 1 to shift must be array (not list) at -e line 1, at end of line Execution of -e aborted due to compilation errors. $ perl -Mstrict -Mwarnings -e 'unshift (1,2,3),1' Type of arg 1 to unshift must be array (not constant item) at -e line 1, near "3)" Execution of -e aborted due to compilation errors. $ perl -Mstrict -Mwarnings -e 'push (1,2,3),1' Type of arg 1 to push must be array (not constant item) at -e line 1, near "3)" Execution of -e aborted due to compilation errors. On 10/29/07, yitzle <[EMAIL PROTECTED]> wrote: > Oops. Duly noted. > Functions/Subs return lists, not arrays. > > But then again, grep() takes a list, and not an array :) > > Arrays can be set from lists and arrays get converted to lists all the time. > Is there any practical difference? (Other than the fact that an array > has a reference which can be passed as a scalar?) > > > Sample code to go along with my previous answer: > > my $str = 'abc,123,,bob'; > my @arr = split ',', $str; > print scalar @arr, " items\n"; # 4 > @arr = grep !/^$/, @arr; > print scalar @arr, " items\n"; # 3 > @arr = grep !/^$/, split ',', $str; > print scalar @arr, " items\n"; # 3 > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
