Thanks a lot !! T
On 10/10/07, Rob Dixon <[EMAIL PROTECTED]> wrote: > > Tatiana Lloret Iglesias wrote: > > > > Hi all! > > > > What regular expression do I need to convert Version: 1.2.3 to > Version: > > 1.2.4 ? > > > > I.e. my pattern is Version: number.number.number and from that i need > > Version: number.number.number+1 > > After the : i can have a space or not... > > Hello Tatiana > > This will do what you need: > > $string =~ s/(Version:\s+\d+\.\d+\.)(\d+)/$1.($2+1)/e; > > Rob > Thanks
