Hi,
my $id = qr(shift); will not work from the same reason that
my $id = "shift" will not work!!!
Yours,
Yaron Kahanovitch
----- Original Message -----
From: "yitzle" <[EMAIL PROTECTED]>
To: beginners@perl.org
Sent: Sunday, August 12, 2007 7:55:38 AM (GMT+0200) Auto-Detected
Subject: qr + shift
Works:
my $t = shift;
my $id = qr($t);
Doesn't work:
my $id = qr(shift);
Why?
Thanks!
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