On Fri, 2007-04-27 at 14:26 -0400, Matthew J. Avitable wrote:
> Pierre,
> >> Thank you, but I got it to work the way I wanted, thanks to Matthew and
> >> Rob's posts:
> >>
> >> map { modify_variable(${$_}) } = \($var1, $var2, $var3);
> >>
>
> To annotate to what Paul said - the above won't work. The block syntax
> of map is "map BLOCK LIST". Plus, it looks like you are going to
> dereference $_ before it gets passed into the function. I'm not
> particularly sure what the statement above will do. :) The following
> should work, if your version of modify_variable treats its first
> argument as a scalar reference. See my earlier post for an example of
> how modify_variable could work.
>
> map { modify_variable($_) } \($var1, $var2, $var3);
Good catch. My code would not have compiled with the '=' sign. I should
pay more attention. Thanks
>
> > And map in void context is generally frowned upon.
> >
>
> There's lots of heated debate about this apparently. I'm certainly not
> into starting a flame war, so I'll just point out an interesting
> conversation which explores this topic, pretty well in depth.
>
> http://www.perlmonks.org/index.pl?node_id=296742
>
>
> -m
>
> --
> + Matt J. Avitable: Senior Systems Analyst, Richweb, Inc.
> + Richweb.com: Providing Internet-Based Business Solutions since 1995
> + (804) 747.8592 x 109
>
>
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
http://learn.perl.org/
