Pierre,
Thank you, but I got it to work the way I wanted, thanks to Matthew and Rob's posts:map { modify_variable(${$_}) } = \($var1, $var2, $var3);
To annotate to what Paul said - the above won't work. The block syntax of map is "map BLOCK LIST". Plus, it looks like you are going to dereference $_ before it gets passed into the function. I'm not particularly sure what the statement above will do. :) The following should work, if your version of modify_variable treats its first argument as a scalar reference. See my earlier post for an example of how modify_variable could work.
map { modify_variable($_) } \($var1, $var2, $var3);
And map in void context is generally frowned upon.
There's lots of heated debate about this apparently. I'm certainly not into starting a flame war, so I'll just point out an interesting conversation which explores this topic, pretty well in depth.
http://www.perlmonks.org/index.pl?node_id=296742 -m -- + Matt J. Avitable: Senior Systems Analyst, Richweb, Inc. + Richweb.com: Providing Internet-Based Business Solutions since 1995 + (804) 747.8592 x 109 -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
