Hi The "8.1.8" =~ /[\d $versao \s]/ will always return true because the square parenthesis ([]) matches the string against one of the chars inside. In this case the \d (digit) matches because you have a digit inside.
In your code you wrote "8.1.8" =~ /$version/. This takes the $version a treat it as a regular expression. I don't think that this is what you want. You actually want something like $version =~ /8\.1\.8/. Yaron Kahanovitch ----- Original Message ----- From: "Rodrigo Tavares" <[EMAIL PROTECTED]> To: [EMAIL PROTECTED] Sent: Wednesday, April 11, 2007 4:30:58 PM (GMT+0200) Auto-Detected Subject: Using regular expressions with delimitaters Hello, I need to use the delimiter " " , (one blank space). I read perdoc, i try to use this : if ( "8.1.8" =~ /[\d $versao \s]/) But the expression is always true. Where is the error ? my code : #!/usr/bin/perl $version=`/usr/local/pgsql/bin/pg_ctl --version`; print $version; if ( "8.1.8" =~ /$version/) { print "$version\n"; } else { print "Wrong version !\n"; } Output, about program: pg_ctl (PostgreSQL) 8.1.8 Wrong version Best regards, Rodrigo Faria __________________________________________________ Fale com seus amigos de graça com o novo Yahoo! Messenger http://br.messenger.yahoo.com/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/