Re: Pattern Matching

[Dharshana Eswaran]

On 1/19/07, Igor Sutton <[EMAIL PROTECTED]> wrote:

I have an update:

> my @data = $string =~ m/0x(\d{2})/g;

my @data = $string =~ m/0x(\S{2}),?/g;

Now I think it is right :)

--
Igor Sutton Lopes <[EMAIL PROTECTED]>

I used the above expression and it worked for me. Thanks you so much.

Thanks and Regards,
Dharshana