Jeff Pang wrote: >> If I have 'my $aryRef = [EMAIL PROTECTED]' can do 'push $aryRef, $aValue'? >> Does this >> place the value of $aValue directly into @array or do I need to figure out >> another way to do that? >> > > You can't do 'push' like this way since $aryRef is a scalar but 'push' expect > a list as its first argument. ^^^^^^ It won't work with a list (or a scalar or a hash or a filehandle, etc.), only with an array.
perldoc -q "What is the difference between a list and an array" John -- Perl isn't a toolbox, but a small machine shop where you can special-order certain sorts of tools at low cost and in short order. -- Larry Wall -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/