On 11/13/06, Tim Wolak <[EMAIL PROTECTED]> wrote:
That worked, so basicly what the \Q \E is doing is searching for non-word characters from the beginning of the line and then stops after the "E$" in my variable?
Not quite right. \Q \E tell that everything in between should be interpreted as literal. That's why 'E$' =~ /\QE$\E/' # beware the quotes "a?" =~ /\Q?\E/ In this vein, /\QE$\E/ is equivalent to /E\$/ and /\Q?\E/ to /\?/. But it works also if you interpolate a variable in the pattern. So that $a = 'E$a?'; /\Q$a\E/ makes at runtime a regexp equivalent to /E\$a\?/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
