Hi folks,
I don't know if this is a Perl or UNIX problem and I'm hoping you can
help me figure that out.
I wrote a script that checks to see if the httpsd and mysqld processes
are running on my server and to log the results of those tests.
When I run the script from the command line, the script prints to a log
file the number of each of those processes that are running at the time
of the script execution. When I run the same script from cron, however,
it only prints a "1" for httpsd and mysqld.
script output to log when run from the command line:
2006-08-12 21:10:20 httpsd 23 mysqld 33
script output to log when run from cron:
2006-08-12 21:11:05 httpsd 1 mysqld 1
Here's the cron entry:
*/15 * * * * perl
/home/james/code/cron_code/httpsd_mysqld_check.pl
Here's the script:
#!/usr/bin/perl
use warnings;
use strict;
my $log_file = '/home/james/code/cron_code/httpsd_mysqld_log_file';
open FILE_OUT, ">> $log_file"
or die "Cannot open log file: $!";
select FILE_OUT;
(my $month, my $day, my $year, my $hour, my $minute, my $second) =
(localtime)[4, 3, 5, 2, 1, 0];
printf("%04s-%02s-%02s %02d:%02d:%02d ", $year+1900, $month, $day,
$hour, $minute, $second);
my $httpsd_count = `ps -aux | grep -c httpsd`;
my $mysqld_count = `ps -aux | grep -c mysqld`;
chomp($httpsd_count);
chomp($mysqld_count);
my $httpsd_msg = '';
my $mysqld_msg = '';
if ($httpsd_count > 0) {
print "httpsd $httpsd_count ";
}
else {
print "httpsd NOT RUNNING ";
}
if ($mysqld_count > 0) {
print "mysqld $mysqld_count ";
}
else {
print "mysqld NOT RUNNING ";
}
print "\n";
close FILE_OUT;
Any ideas on why the same script has different results when run from
the command line vs. from cron?
Thanks,
James
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