Don't write it like this.Consider this case:
$ARGV[0] ==0;
then your statement :
my $time_in = $ARGV[0] || <STDIN>;
should be broken.
--Jeff Pang
-----Original Message-----
From: [EMAIL PROTECTED]
To: beginners@perl.org
Sent: Wed, 6 Sep 2006 1:58 PM
Subject: Re: pipe as an argument
On 9/6/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
Consider this:
my $arg = @ARGV ? shift @ARGV : <STDIN>;
Works as I expected, many thanks.
However, my previous code was:
my $time_in = $ARG[0] || <STDIN>;
and it doesn't work, why and whats the different with yours?
rgds,
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