Here's one example of how you could go about it:
##########################
use strict;
use warnings;
my $testString = " test_freq = 1.0001;";
print "Test One: ";
if($testString =~ /=\s*([0-9.]+)\s*;\s*$/){
print $1;
}else{
print "Failed!";
}
print "\n";
##########################
'[0-9.]' is a character class that represents the numbers zero through
nine and the period character.
I added in a few '\s*' matches in case there were spaces before and
after the semicolon. This should be specific enough to match only a
number that is a n rvalue.
-----Original Message-----
From: Ryan Moszynski [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 27, 2006 1:27 PM
To: beginners@perl.org
Subject: reg ex problem
i have this string extracted from a text file i'm writing a program to
process:
test_freq = 1.0001;
and i have to extract the "1.0001"
i can't count on the whitspace being where it now is.
I would like to change this line of perl
$getTestFRQ =~ s/\D+//g;
so that instead of killing all non digit characters, it will kill all
non digit characters except for the period.
How do i do this?
thanks, ryan
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