Re: want regex to produce a scalar which is defined when no match

[Sumo Wrestler (or just ate too much)]

tom arnall wrote:

[...]

why does '(m{0,1})' produce an empty scalar, while '(m){0,1}' an undefined scalar?

and what i'm really after is to say:

        ($f,$g,$h)=/(a{0,1})(m|mn){0,1}(b{1,1})/;
        
and have $g come out a scalar which is defined.

Use the grouping syntax to group together m and mn like so:
($f,$g,$h)=/(a{0,1})((?:m|mn){0,1})(b{1,1})/;


(?:) groups without capturing.
$ man perlre

thanks,

You're welcome.




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