On Fri, 2006-05-05 at 11:29 +0100, Steve Swift wrote:
> I've written a tiny program to make it easy to test the syntax and
> effects of a Perl statement. My program is called "perltry" and here it
> is in its full gory (pun intended)
>
> #!/usr/bin/perl
> use strict;
> use warnings;
> system('clear');
> system('perl -v');
> print "Go on - try a few... Enter 'exit' to end.\n";
> while (<>) {
> eval $_;
> if ($@) {print "[EMAIL PROTECTED]";}
> print ' ','.'x50," perltry on $^O\n"
> };
>
> If I enter a statement, such as "$a=1;" (without the quotes) then I
> would expect that scalar $a would get the value 1. If I then enter the
> statement "print $a" I expected to see "1". What I saw was:
> Use of uninitialized value in string at (eval 2) line 1, <> line 2.
>
> Could someone tell me why this happened, please?
> Is it possible to change this so that the variable $a would get set?
It works on my machine.
You could try my favourite Perl one-liner, the Perl calculator:
perl -ple '$_=eval'
or on DOS:
perl -ple "$_=eval"
See `perldoc perlrun` and `perldoc -f eval` for details.
--
__END__
Just my 0.00000002 million dollars worth,
--- Shawn
"For the things we have to learn before we can do them, we learn by doing them."
Aristotle
* Perl tutorials at http://perlmonks.org/?node=Tutorials
* A searchable perldoc is at http://perldoc.perl.org/
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