On 4/11/06, John W. Krahn wrote: > > This is probably trivial, but I couldn't find a mention of this > > anywhere - why do the following 2 code lines produce different > > results? > >>perl -e 'printf "%d\n" ,0xffff_ffff' > > -1 > >>perl -e 'print 0xffff_ffff , "\n"' > > 4294967295 > > perldoc perlnumber >
Hi John, Thanks for the pointer, I guess you wanted me to see the "All the operators which need an argument in the integer format treat the argument as in modular arithmetic" sentence. But why is "print" behaving differently? I.e., why is the 0xffff_ffff not treated as a number? Thanks, -- Offer Kaye -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
