Robert Hicks: > I have an application log that shows the "time", "id" and "type" for > a user logging in. A short except looks like this: > > 19/12/2005 07:28:37 User (guest) logging in from (LIMS-CIT) - > Assigned Userno (7045) > 19/12/2005 07:32:06 User (guest) logging in from (LIMS-CIT) - > Assigned Userno (1959) > 19/12/2005 07:51:38 User (guest) logging in from (LIMS-CIT) - > Assigned Userno (7601) > 19/12/2005 07:54:10 User (guest) logging off - Userno (7601) > > I need to get the difference in the time from when 7601 logged into > the system and logged out of the system. The caveat is that 7601 > could log in and log out multiple times. I am having a hard time > thinking about how to do that. > > Should I find the first login and look for the logout, get the diff > and reset some counter. Do I use a hash for this? > > Just a little push (not off the cliff please)...is all I need.
perldoc -q nesting CPAN, search for 'parse' Maybe adjust Parse::Syslog. For the order, don't rely on the Date + Time but also store a linenumber. -- Affijn, Ruud "Gewoon is een tijger." -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
