On Nov 29, 2005, at 10:42, Bedanta Bordoloi, Gurgaon wrote:
No, $log_entry[0] holds a string, and we are getting the error as
** is a
part of that string.
Interpolation in regexps is done before the regexp is interpreted as
such. For instance, if $foo is "*" and we have
/.*$foo/
first interpolation is done giving
/.**/
and that is interpreted as a regexp, which in this case is invalid
and would raise an error.
In consequence, metacharacters in interpolated strings need to be
escaped to be treated literally, and this is easy to get:
$str =~ s/(^\Q$log_entry[0]\E\s)//i
There we start escaping with \Q, and end it with \E, so that "\s)" is
interpreted as part of the regexp as is. If you wanted to escape the
very string outside the regexp there's quotemeta().
-- fxn
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