Moon, John wrote:
> Does any one know how to do this with just a substitution?
>
> perl -e '$a=q{Data.m1234.D1234567890};
> $a =~/\d+$/;
> $numbers = q{#} x length($&);
> $a=~ s/\d+$/$numbers/; print "$a\n";'
>
> What " Data.m1234.D########## " as a result.
>
> John W Moon
Did the following:
perl -e '$a=q{Data.m1234.D1234567890};
$a =~ s/(\d+)$/'#'x length($1)/e;
print "$a\n";
output was:
Data.m1234.D##########
Wags ;)
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