Does perl allow you to conditionally include a module? For example:
#!/usr/bin/perl -w use strict; my $DEBUG = 0; if (DEBUG) { use diagnostics; } my $filename = "test$$.txt"; open (FH , ">$filename") || die "error: $!"; print (FH "hi"); close (FH); Although this is a simple and silly example, it would be nice to be able to include the diagnostic module by setting my debug to true. Any Comments? DA -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>