On Jul 22, Brent Clark said:
Think I have a better unstanding of the use of () for my regex search, but
this morning I have a new set of problems, whereby I need to perform a search
and replace and then pass on to the new variable.
My current code is as so, and works:
$_ =~ s/(^\w+\.dat\|)//;
my $lineExtract = $_;
I'd ask first why you've got something in $_. You might be able to save
time by putting the content directly into $lineExtract.
Also, you don't need to say '$_ =~' when doing a pattern match or
substitution against $_; it's implied:
s/foo/bar/; # works on $_
This one-liner stores $_'s contents in $lineExtract, and THEN runs the
substitution on $lineExtract (keeping $_ intact):
(my $lineExtract = $_) =~ s/.../.../;
But again, I'm curious how you got stuff into $_ that you want to copy to
another location anyway.
--
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