Dear list,
i'am just wondering about the behaviour of shift and the defaultvariable @_ . I use the following code:: while (<RULEFILE>) { # each line of RULEFILE is stored in $_ chomp; # delete \n from $_ split /;/; # split the fields of $_ seperated by ; into @_ print "Array before shift: @_\n"; # prints @_ my $test = shift @_; # $test gets the first item from @_ print "Array after shift: @_\n"; # print @_ without the first item } everything works fine. Now i change the line "my $test = shift @_" into "my $test = shift". This should work because shift should use @_ by default. But in this case $test is empty an the second print command prints still the whole @_. I really don't know why this should not work? I would be happy about any help. Greetings Mathias -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>