Hi , in $prog =~ s/^.*\///; is it trying to substitute all characters until the last / within $prog?
meena --- MEENA SELVAM <[EMAIL PROTECTED]> wrote: > Hi, > > can anyone please explain? > > In the following code snippet, what is the meaning > of > the pattern match > s/^.*\/// > > $prog = $0; > $prog =~ s/^.*\/// > > i did not get details when i searched in google > thanks, > meena > > > > ____________________________________________________ > > Yahoo! Sports > Rekindle the Rivalries. Sign up for Fantasy Football > > http://football.fantasysports.yahoo.com > > -- > To unsubscribe, e-mail: > [EMAIL PROTECTED] > For additional commands, e-mail: > [EMAIL PROTECTED] > <http://learn.perl.org/> > <http://learn.perl.org/first-response> > > > ____________________________________________________ Yahoo! Sports Rekindle the Rivalries. Sign up for Fantasy Football http://football.fantasysports.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
