This was not a home work. In a real script I need to change the last element of the array. Not changing the array it self.
I work with Perl for more than 4 years now. And after 4 years, I need this. Thanks MArcos On Thu, 10 Mar 2005 09:06:52 -0600, Larsen, Errin M HMMA/IT <[EMAIL PROTECTED]> wrote: > > -----Original Message----- > > From: Wiggins d'Anconia [mailto:[EMAIL PROTECTED] > > Sent: Thursday, March 10, 2005 8:55 AM > > To: Marcos Rebelo > > Cc: Perl Beginners > > Subject: Re: Simplify perl -e '$a = [1,2,3,4,7]; print $a->[EMAIL > > PROTECTED]' > > > > > > Marcos Rebelo wrote: > > > This is correctly printing '7' but '$a->[EMAIL PROTECTED]' seems to be > > > encripted code. > > > > > > Can I write this in a cleaner way? > > > > > > > > > > $a->[-1]; ??? > > > Hi Wiggins, > > for those of us tryin' to keep up at home, can you walk us through > that bit a little? > > Here's what I spot: > > $a = [1,2,3,4,7] # this is initializing a scalar, $a, with a reference > to an array, [1,2,3,4,7] > > # $a-> this is dereferencing the array > # as I understand it, and I really don't, the $#ARRAYNAME will give you > the number of elements, minus one, of an array? > # if that is the case, and then [EMAIL PROTECTED] ALSO derefernces the > array, so > then > # [EMAIL PROTECTED] will be the number of elements in the array referenced by > $a, minus one (or, '4', in this example) > > # so > print $a->[EMAIL PROTECTED] > > # is equivelant to > print $a->[4] > > # or, since [EMAIL PROTECTED] will always be the index of the last element of > the > array: > print $a->[-1] > > Did I get it right? That looks like homework to me ... Why would you > ever do that in a practical script? > > --Errin > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > <http://learn.perl.org/> <http://learn.perl.org/first-response> > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
