Hello,
Are you sure that
%THE_COMMANDS( open => &dosomething );
is not
%THE_COMMANDS( open => \&dosomething );
The \ in front of the & makes $THE_COMMAND{open} a code reference. And
the way you dereference a code ref is with the -> operator. It's the
same as if I did.
my $open = \&dosomething;
$open->($THE_COMMAND);
You can get a better understanding of references from here:
http://www.perlmonks.org/index.pl?node_id=137108
Hope this helps,
Robert Boone
On Fri, 2005-01-14 at 12:10 -0500, radhika sambamurti wrote:
> Hi,
> I am the "maintenance programmer" for this large chunk of code. My
> question is particular to this syntax:
>
> $THE_COMMANDS{$THE_COMMAND}->($THE_COMMAND);
> Where THE_COMMANDS is a hash
>
> %THE_COMMANDS( open => &dosomething );
> Thus, $THE_COMMANDS{$THE_COMMAND} is nothing but &dosomething right?
> so why cant I issue the command by saying: $THE_COMMANDS{$THE_COMMAND};
> I tried that and it did not work.
> I actually had to use: $THE_COMMANDS{$THE_COMMAND}->($THE_COMMAND);
> I guess I am a bit confused. Any help in way of what to read further to
> aid my understanding of this would also be helpful.
>
> thx,
> radhika
>
> --
> It's all a matter of perspective. You can choose your view by choosing
> where to stand.
> Larry Wall
> ---
>
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