Ing. Branislav Gerzo <[EMAIL PROTECTED]> wrote:
: Charles K. Clarkson [CKC], on Monday, November 15, 2004 at
: 09:20 (-0600) typed:
:
: : : $seen{$item} ? $seen{$item}++ : $seen{$item} = 1; }
: : $seen{$item} = $seen{$item} ? ++$seen{$item} : 1;
:
: ok I understand, but I don't know why my line doesn't work. I
: thought (exp) ? (true) : (false) is the same as if (exp) { }
: else { }
Further investigation leads me to believe perl interpreted
your original statement:
$seen{$item} ? $seen{$item}++ : $seen{$item} = 1;
As this:
( $seen{$item} ? $seen{$item}++ : $seen{$item} ) = 1;
When you probably meant this:
$seen{$item} ? ($seen{$item}++) : ($seen{$item} = 1);
According to the docs: "The operator may be assigned to
if both the 2nd and 3rd arguments are legal lvalues." A
post increment is not a valid lvalue. You are basically
saying this.
if ( $seen{$item} ) {
$seen{$item}++ = 1;
} else {
$seen{$item} = 1;
}
HTH,
Charles K. Clarkson
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