JupiterHost.Net [JN], on Wednesday, September 15, 2004 at 16:52
(-0500) made these points:
>> my $foo = 'test';
>> my @bar = ( 'foo', '[%foo%]', 'bar' );
JN> The question would be why you're doing ${$1} since nothing in @bar is a
JN> reference.
I want change [%foo%] to $foo, so I expect in result 'test' as before
defined.
JN> I think you want:
JN> $x =~ s/^\[%([^%]+)%\]$/$1/g;
no, that gives me:
foo foo bar
and I don't want to.
--
...m8s, cu l8r, Brano.
[Your Ex just called - she's with the IRS now]
-=x=-
Skontrolované antivírovým programom NOD32
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