Hi,
Whenever you pass two arrays (or any number of arrays for that matter)
as arguments to a function, what happens is they get flattened and
become a single list and then it is assigned to @_.
So when U say
>
> my (@array1, @array2) = @_; # is this correct? How do I do it?
>
@array1 has the entire @_ (which is now having a single list that was
constructed with the 2 arrays passed to the function)
For example when you have a piece of code like
@arr1 = ("Sun", "Mon");
@arr2 = ("Tue", "Wed");
@arr3 = (@arr1, @arr2);
Now @arr3 has a single list with Sun, Mon, Tue and Wed as values. This
is because of the nature of Perl flattening arrays inside a list.
A solution for you is to pass the arrays as reference and then
dereference it inside the function...
Example:
========
#!/usr/local/bin
use strict;
my @arr1 = (1, 2, 3, 4);
my @arr2 = ('One', 'Two', 'Three', 'Four');
&mysub([EMAIL PROTECTED], [EMAIL PROTECTED]);
sub mysub {
my ($a_1, $a_2) = @_;
for my $var (@{$a_1}) {
print "$var in words is ${$a_2}[$var-1]\n";
}
}
Output:
=======
1 in words is One
2 in words is Two
3 in words is Three
4 in words is Four
Hope this is useful for you.
For more on references go through "perldoc perlref"
With Best regards,
R. Kamal Raj Guptha.
-----Original Message-----
From: Edward Wijaya [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 05, 2004 3:37 PM
To: [EMAIL PROTECTED]
Subject: How to pass two arrays as arg in a subroutine?
Hi,
I have a subroutine that take 2 arrays as argument.
I dont' know how to construct it?
sub mysub{
my (@array1, @array2) = @_; # is this correct? How do I do it?
#process @array1
#process @array2 etc
return @array3;
}
Please advice.
Thanks so much for your time.
Regards,
Edward WIJAYA
SINGAPORE
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