On Fri, 30 Jul 2004, Andrew Gaffney wrote:
Chris Devers wrote:
On Fri, 30 Jul 2004, Andrew Gaffney wrote:
Then yes, I misunderstood. This version should do what you want:
$ find /path/to/htdocs -type f | xargs egrep -liv '<%(perl|init)>'
That still doesn't appear to do what I want. I believe it is showing me all files where *all* lines don't contain '<%perl>' or '<%init>'. Since not *all* lines contain either one of those, all files still show in the list.
Okay, let's try again then:
$ grep -li '<title>' *html # print all html files with '<title>' 20things.html bookmarks.html gas.html gas_form.html itunes.html noise.html $
$ grep -Li '<title>' *html # print all html files WITHOUT '<title>' HEADER.shtml $
The sets are non-intersecting, and so apparently what you meant.
If you want to refine this further, try `egrep --help` or `man egrep`.
I should have tested what I sent before sending it, but ten seconds of skimming over the documentation on your own should have been enough to show you these lines from `egrep --help`:
$ egrep --help | grep -i 'files.*match.*print' -L, --files-without-match only print FILE names containing no match -l, --files-with-matches only print FILE names containing matches $
So, as with many Unix commands, shift-L inverts the usual sense of L, meaning that '-L' gets you the opposite of what '-l' does.
Now have we got it? :-)
I think it is a problem with the regex. If I change it to:
grep -RLi '<%init>' * | grep '.html'
I get all files that don't have '<%init>', but it doesn't work with the '<%(init|perl)>'. That regex doesn't seem to match anything.
-- Andrew Gaffney Network Administrator Skyline Aeronautics, LLC. 636-357-1548
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