Hello all, Will really appreciate help with this: I'm pulling my hair out with this one.
I have a list of contents in the @contents array and the script finds those headings in the html and adds anchors to them. The trouble is, the substitution won't match when there's a question mark in the content item: I've quoted the pattern in the if loop but it won't work in a subtitution. Clearly the question mark is being treated as a regex operator (0 or1) rather than the literal. So, items 2 and 3 on the list below are not being matched - how do I quote the scalar $item, question marks and all, in the substitution below? Contents list: Background Why China needed asset management? The scope of operation for AMCs in China? Ongoing AMC business in China Asset management as part of China's overall financial reforms The persistent problem of China's SOEs Foreign participation in China's asset management sector Conclusion Information sources Script: foreach $item (@contents) { if (q/<p><b>$item<\/b><\/p>/) { my $abbrev = $item; $abbrev =~ s/(.....).*/$1/; $abbrev =~ s/ //g; print "$item\n"; s/<li>${item}<\/li>/<li><a href="\#$abbrev">$item<\/a><\/li>/; s/<p><b>${item}<\/b><\/p>/<br>\n<p><span class="fauxh3"><a name="$abbrev">$item<\/a><\/span><\/p>/; } else { print "$item\n"; } } -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>