use Time::Local;
# localtime cannot handle year 1903, but timelocal can print scalar timelocal(0,0,0, 31, 11, 2003), "\n"; print scalar timelocal(0,0,0, 31, 11, 1903), "\n";
print scalar localtime timelocal(0,0,0, 31, 11, 2003), "\n"; print scalar localtime timelocal(0,0,0, 31, 11, 1903), "\n";
Output: 1072846800 -1830643200 Wed Dec 31 00:00:00 2003 Use of uninitialized value in print at E:\Documents\Perl\scratch.pl line 11.
Well, the number of epoch seconds returned by timelocal() may be negative, while localtime() returns undef if a negative number is passed to it. Just as expected due to
perldoc Time::local
and
perldoc -f localtime
But you're asking "why?". Guess you need to ask the perl porters. ;-)
-- Gunnar Hjalmarsson Email: http://www.gunnar.cc/cgi-bin/contact.pl
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