Hi hdan, try \$ for $. I did not test it anyway. HTH, Jay -----Original Message----- From: hdan [mailto:[EMAIL PROTECTED] Sent: Thursday, April 22, 2004 1:13 PM To: [EMAIL PROTECTED] Subject: backtick variable substitution
Hi all, Hopefully someone can help me out with this one. I have a perl script that runs rsh commands to monitor a remote server. To minimize time and bandwidth I need to maximize the processing that is done on the remote server and minimize the number of rsh commands done. My question is, how can I place a while loop within a system call so that the loop variable is substituted correctly? Here is an example: $THE_ERRORS = `rsh remote_box "cat -n app_error.log | grep -E 'error' | cut -f 1 | while read x; do head -$x app_error.log | tail -2; done"`; Basically, I'm trying to get the error message line and the line before it returned into $THE_ERRORS. The problem is that $x is not being interpreted correctly by the head command. For simplicity, we can take the whole rsh out of the picture and use this as an example: $THE_ERRORS = `cat -n app_error.log | grep -E 'error' | cut -f 1 | while read x; do head -$x app_error.log | tail -2; done`; Thanks for any suggestions. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
