In this case, $func holds a "hard reference", not a "soft reference". The strict pragma only blocks the latter.
Here's a simple example:
sub howdy { print "Howdy!\n"; }
my $func = \&howdy; # hard reference $func->(); # fine, even with strictures
$func = 'howdy'; # soft reference, name only $func->(); # will not pass strictures
Hope that helps.
Very much so! Thx a million :)
James
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