Hi Stuart. Stuart White wrote: > > <snip> > > > > Of course, then all the numbers are squished > > together. > > > (How else might I say that?) > > > > I don't know, what do you mean by "squished > > together"? > > > without spaces between each number. (it was late last > night and I had a mental block.)
My guess is that you're looking at the output from print @list; which 'squishes' the values. Look: my @list = 'A' .. 'F'; print @list, "\n"; print "@list", "\n"; **OUTPUT ABCDEF A B C D E F > > > So my solution is to > > > "stringify" the array of numbers by putting the > > array > > > inside double quotes and assigning it to itself. > > That > > > seems to work. > > > > How does that "seem to work"? > > Well, it seemed to work because I thought that I was > getting those numbers into an array, an element for > each number. But as you point out later, I just got > them into the first element. > > <snip> > So when I get the number from the user, I thought that > the simplest way to get all the numbers in between was > to use the range operator, and then store those > numbers into an array. Is there a way I can do that? > Is using the range operator not a good way to go about > getting the numbers in between and then storing them > into an array? Your code is exactly right: well done. You don't even need to chomp the input: my $input = " 22 \n"; my @list = (2 .. $input); print "list first: @list\n"; **OUTPUT list first: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 I hope this helps. I smell a misconception here, which may end up with us talking at cross-purposes; but please come back to the list if you're puzzled about anything. HTH, Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
