The error was:
useless use of lc in void context at line 22

I also tried this:
lc($input = <STDIN>);
print "$input";


> This won't work though because chomp() returns the
> number of newline
> characters removed from the string... so in essence
> you are trying to
> lowercase the number "0" or "1" (the return value of
> chomp).  ...Not to
> mention that you lc() does not modify the scalar
> passed as an argument (like
> chomp does), so you need to store the result of
> lc().
>
 
This makes sense, but I didn't know about it.


> This is what you want:
> 
> chomp($input = <STDIN>);
> $input = lc($input);
> print $input;
> 
> Rob
> 

Thanks, that worked.


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