[EMAIL PROTECTED] wrote:
> > B. Rothstein wrote:
> > > Does anyone have any suggestions on how to create an array to
> > > hold the value of 1000 factorial?
> >
> > This will compute it:
> >
> > perl -MMath::BigInt -le '$n = Math::BigInt->new("1"); $n *= $_ for
> > 2..1000; print $n'
> >
>
> in trying to understand this i guess that:
>
> $n = Math::BigInt->new("1");
>
> assigns n a value of 1 and a type "BinInt"
>
> using the "new" proc with-in module "Math::BigInt"
Yep. new() is a constructor, so $n is an object in the class Math::BigInt.
>
> the the usual multiplying of 1000 by the number below it...
Yes, except that the multiplication operator is overloaded for Math::BigInt
objects, so this multiplication operation is turned into a method call.
see perldoc Math::BigInt
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