Howdy list: Trying to do an inplace edit:
perl -pi -e 's/whatever/newstuff/;' /file/path/here What I need to do is replace certain parts of the line for instance: s/^$var:(.*):123:def/$var:\1:456:ghi/; Soo if a line matches the $var at the beginning a colon, some stuff, a colon, 123, a colon, def Replace that with $var, a colon, *whatever was in "some stuff"*, a colon , 456, a colon, ghi It seems like that parens and \1 combo ought to do it but I can't get that to work! The file does get modified so I have permission it's just that \1 is empty on the result and has data before I run the command. And no I'm not messing with /ets/passwd files :) I'm runing Perl 5.8 on redhat 9 if that makes a difference. TIA Dan -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
