> if (defined $x and length $x)
So, is this the opposite?
if (! defined $x and length $x)
or do I have to parenthesis
if (! (defined $x and length $x))
-rkl
> On Oct 2, [EMAIL PROTECTED] said:
>
>>To recap, I want to test if a var is undefined or ''.
>>
>> if(undefined $x && length($x)==0)
>
> There IS no 'undefined' function in Perl, and you don't want to use &&,
> you'd want to use ||, since the empty string "" IS defined.
>
> if (not defined($x) or length($x) == 0) {
> # it's undef OR ""
> }
>
> Or, do it the other way:
>
> if (defined $x and length $x) {
> # it's NOT undef, and it's NOT ""
> }
>
> --
> Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
> RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
> <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
> [ I'm looking for programming work. If you like my work, let me know. ]
>
>
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