Hi
all,
I am trying to write
a regular expresion to get a file path from a cron file, I have issolated the
required lines, but am having problems with extracting just the file path and
name.
The line is as
follows :
30 23 * * *
/usr/lbin/sa/sa1 600 6
I inned to
extract just the '/usr/bin/sa/sa1' section.
Any guidance
would be appreciated.
Jas
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