from Gary Stainburn: >> print "xor1" if ($a = $a) ^ ($b = $c); > >Presumably this is because you're using the assignment operator and not the >comparison operator. > >print "xor1" if ($a == $b) ^ ($b == $c);
interesting.. a '=' seems to work fine in an 'and' or 'or' statement-- using 'xor' in place of '^' seems to work also--- another response by John W. Krahn [EMAIL PROTECTED] :: >At the bit level >they work the same as the example above. (referering to using "and" "or" "xor" vs "&" "|" "^" etc...) > If you use them on numbers or >strings they modify each bit of the number or string according to the >example above. >perldoc perlop i will have to go over this documentation more thoroughly, i can now use the tool- but understanding it is another thing entirely. thanks much :) -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
